{"id":18172,"date":"2024-03-09T20:42:47","date_gmt":"2024-03-09T20:42:47","guid":{"rendered":"https:\/\/soicau5052.minhngocxoso.com\/?p=18172"},"modified":"2024-03-09T20:42:47","modified_gmt":"2024-03-09T20:42:47","slug":"dan-dac-biet-25-so-nuoi-khung-5-ngay-va-cach-vao-tien","status":"publish","type":"post","link":"https:\/\/dudoanxosomientrung.com\/dan-dac-biet-25-so-nuoi-khung-5-ngay-va-cach-vao-tien\/","title":{"rendered":"d\u00e0n \u0111\u1eb7c bi\u1ec7t 25 s\u1ed1 nu\u00f4i khung 5 ng\u00e0y v\u00e0 c\u00e1ch v\u00e0o ti\u1ec1n"},"content":{"rendered":"
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D\u00e0n \u0111\u1ec1 25 s\u1ed1 nu\u00f4i 3 ng\u00e0y l\u00e0 c\u00e1ch ch\u01a1i m\u00e0 anh em c\u1ea7n l\u1ef1a ch\u1ecdn ra b\u1ed9 khung g\u1ed3m 25 con s\u1ed1 \u0111\u1ec3 \u0111\u00e1nh li\u00ean t\u1ee5c trong 3 ng\u00e0y sau \u0111\u00f3, m\u1ee9c ti\u1ec1n c\u01b0\u1ee3c s\u1ebd t\u0103ng d\u1ea7n t\u1eeb ng\u00e0y th\u1ee9 1 \u0111\u1ebfn ng\u00e0y th\u1ee9 3 \u0111\u1ec3 \u0111\u1ea3m b\u1ea3o khi con \u0111\u1ec1 v\u1ec1 b\u1ea5t k\u1ec3 ng\u00e0y n\u00e0o th\u00ec anh em v\u1eabn \u0111\u1ec1u lu\u00f4n c\u00f3 l\u00e3i.<\/p>\n\n\n\n
Theo chuy\u00ean gia, m\u1ee9c ti\u1ec1n c\u01b0\u1ee3c \u0111\u01b0\u1ee3c g\u1ee3i \u00fd l\u00e0 1:3:7, c\u1ee5 th\u1ec3:<\/p>\n\n\n\n
Ng\u00e0y 1: \u0110\u00e1nh 25 con m\u1ed7i con 10.000\u0111 = 250.000\u0111. N\u1ebfu th\u1eafng s\u1ebd \u0103n \u0111\u01b0\u1ee3c 10.000 x 99 = 990.000 l\u00e3i = 990.000 \u2013 250.000 = 710.000\u0111.<\/p>\n\n\n\n
Ng\u00e0y 2: C\u01b0\u1ee3c 25 s\u1ed1 m\u1ed7i s\u1ed1 30.000\u0111 = 750.000\u0111. T\u1ed5ng v\u1ed1n 2 ng\u00e0y = 750.000 + 250.000 = 1 tri\u1ec7u. N\u1ebfu th\u1eafng s\u1ebd \u0103n \u0111\u01b0\u1ee3c 30.000 x 99 = 2.970.000\u0111 => L\u00e3i sau c\u00f9ng = 2.970.000 \u2013 1.000.000 = 1.970.000\u0111.<\/p>\n\n\n\n
Ng\u00e0y 3: C\u01b0\u1ee3c v\u1edbi s\u1ed1 ti\u1ec1n 70.000\u0111 = 1.750.000\u0111. T\u1ed5ng v\u1ed1n = 1.750.000 + 1.000.000 = 2.750.000\u0111. N\u1ebfu \u0111\u1ec1 v\u1ec1 th\u00ec anh em s\u1ebd th\u1eafng \u0111\u01b0\u1ee3c 70.000 x 99 = 6.930.000\u0111 => Ch\u1ed1t l\u00e3i = 6.930.000 \u2013 2.750.000 = 4.180.000\u0111.<\/p>\n\n\n\n
Qu\u1ea3 l\u00e0 m\u1ed9t kho\u1ea3ng ti\u1ec1n l\u00e3i h\u01a1n c\u1ea3 mong \u0111\u1ee3i \u0111\u00fang kh\u00f4ng n\u00e0o? Anh em l\u01b0u \u00fd l\u00e0 n\u1ebfu con \u0111\u1ec1 v\u1ec1 r\u1ed3i th\u00ec n\u00ean d\u1eebng v\u00e0 ch\u1ecdn m\u1edbi m\u1ed9t b\u1ed9 s\u1ed1 kh\u00e1c \u0111\u1ec3 nu\u00f4i.<\/p>\n\n\n\n D\u00e0n \u0111\u1eb7c bi\u1ec7t 25 s\u1ed1 nu\u00f4i 5 ng\u00e0y l\u00e0 c\u00e1ch ch\u01a1i m\u00e0 anh em c\u1ea7n l\u1ef1a ch\u1ecdn m\u1ed9t b\u1ed9 25 con \u0111\u1ec3 \u0111\u00e1nh trong 5 ng\u00e0y li\u00ean ti\u1ebfp.<\/p>\n\n\n\n \u0110a ph\u1ea7n c\u01b0\u1ee3c th\u1ee7 ch\u1ec9 d\u00e1m ch\u01a1i trong ph\u1ea1m vi 3 ng\u00e0y, ch\u1ec9 c\u00f3 nh\u1eefng cao th\u1ee7 n\u00e0o c\u00f3 ngu\u1ed3n v\u1ed1n l\u1edbn v\u00e0 \u0111\u1ee7 b\u1ea3n l\u0129nh th\u00ec m\u1edbi d\u00e1m ch\u01a1i 5 ng\u00e0y, tuy nhi\u00ean s\u1ed1 ti\u1ec1n th\u01b0\u1edfng nh\u1eadn \u0111\u01b0\u1ee3c c\u0169ng r\u1ea5t x\u1ee9ng \u0111\u00e1ng v\u1edbi s\u1ed1 ti\u1ec1n v\u00e0 c\u00f4ng s\u1ee9c m\u00e0 anh em \u0111\u00e3 b\u1ecf ra.<\/p>\n\n\n\n Theo chuy\u00ean gia, anh em n\u00ean ch\u01a1i v\u1edbi m\u1ee9c c\u01b0\u1ee3c l\u00e0 1:3:7:11:17, ti\u1ebfp t\u1ee5c \u1edf ng\u00e0y th\u1ee9 4:<\/p>\n\n\n\n Ng\u00e0y 4: Ti\u1ec1n c\u01b0\u1ee3c l\u00e0 110.000\u0111 s\u1ebd t\u01b0\u01a1ng \u0111\u01b0\u01a1ng v\u1edbi 2.750.000\u0111. T\u1ed5ng v\u1ed1n = 2.750.000 + 2.750.000 = 5.500.000\u0111. N\u1ebfu G\u0110B v\u1ec1 th\u00ec l\u00e3i l\u00e0 110.000 x 99 = 10.890.000\u0111 => Ch\u1ed1t l\u00e3i 4 ng\u00e0y = 5.390.000\u0111.<\/p>\n\n\n\n Ng\u00e0y 5: M\u1ee9c c\u01b0\u1ee3c l\u00e0 170.000\u0111\/con t\u01b0\u01a1ng \u0111\u01b0\u01a1ng v\u1edbi 4.250.000\u0111. T\u1ed5ng c\u01b0\u1ee3c = 4.250.000 + 5.500.000 = 9.750.000\u0111. N\u1ebfu \u0111\u1ec1 n\u1ed5 anh em l\u00e3i 170.000 x 99 = 16.830.000\u0111. Ch\u1ed1t \u0103n sau ng\u00e0y 5 = 7.080.000\u0111.<\/p>\n\n\n\n D\u00e0n \u0111\u1ec1 25 s\u1ed1 \u0111\u1ec3 th\u1eafng ngay trong ng\u00e0y \u0111\u00e3 kh\u00f3 v\u1eady m\u00e0 nhi\u1ec1u anh em cao th\u1ee7 c\u00f2n d\u00e1m b\u1ecf ra s\u1ed1 ti\u1ec1n c\u01b0\u1ee3c h\u00e0ng ch\u1ee5c tri\u1ec7u \u0111\u1ed3ng \u0111\u1ec3 nu\u00f4i khung li\u00ean t\u1ee5c t\u1eeb 3 \u2013 5 ng\u00e0y li\u00ean ti\u1ebfp.<\/p>\n\n\n\n \u0110\u1eebng h\u1ecfi v\u00ec sao c\u00e1c cao th\u1ee7 l\u1ea1i v\u00e0o b\u1edd nhi\u1ec1u v\u00e0 l\u1ea1i ki\u1ebfm \u0111\u01b0\u1ee3c r\u1ea5t nhi\u1ec1u ti\u1ec1n t\u1eeb h\u00ecnh th\u1ee9c c\u00e1 c\u01b0\u1ee3c n\u00e0y, anh em c\u0169ng n\u00ean c\u1ed1 g\u1eafng t\u1ef1 trau d\u1ed3i kinh nghi\u1ec7m c\u1ee7a m\u00ecnh sau m\u1ed7i k\u1ef3 quay \u0111\u1ec3 c\u00f3 th\u1ec3 lu\u00e2n phi\u00ean s\u1eed d\u1ee5ng nhi\u1ec1u c\u00e1ch \u0111\u00e1nh kh\u00e1c nhau<\/p>\n\n\n <\/p>\r\nD\u00e0n \u0111\u1eb7c bi\u1ec7t 25 s\u1ed1 nu\u00f4i khung 5 ng\u00e0y v\u00e0 c\u00e1ch v\u00e0o ti\u1ec1n<\/h2>\n\n\n\n
L\u1eddi k\u1ebft<\/h2>\n\n\n\n
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